1 of 19 If a parabola's focus is at (3,8) and directrix is at y = 2, what is the vertex form of the equation representing this parabola? O y= 1(2-3)3 +3 O y= 1(x-3)3 +5 O y= !(x +3)3 +8 O y= - 4(x+3)3 -5-10 P (X, y ) F ( -2,5 ) -12 -6 N -10 -8 -4 -2 4 10 y=-1 What is the equation of the parbola shown below, given the focus at F(-2,5) and the directrix y = -1? Identify the vertex and the equation of the axis of symmetry of the parabola. O y= 1(x+2)' +2 ; vertex (-2,2); axis of symmetry is a = -2 O y= 1(z + 2)3 +2; vertex (-2, 2); axis of symmetry is = = -2 O y= -1(2+2)3 +2; vertex (2, 2); axis of symmetry is a = 2 O y= (x -2)' +2, vertex (2,2); axis of symmetry is = = 53 of 19 The equation of a quadratic relation is y = 1(@-3)3 +3. Every point on this conic is equidistant from the focal point (a, b) and the line defined by y = c. Determine the value of a + b +c. 0 9 O 10 O 7 O 84 of 19 Find the centre and radius of the circle a +y' + 6x -4y -23 = 0. O centre (-3, 2), radius 6 O centre (-3, -2), radius 6 O centre (3,2), radius 6 O centre (-3,2), radius v65 of 19 What is the equation of the circle with centre (&,o) and radius 2? O (2x - 1)- 2 +y = 2 O (2x - 1)' 4 +y =4 O (2x - 1)' 4 + 1 = 2 O (2x - 1)- 2 +y =46 of 19 Write the equation of a circle with centre (-8, -3) which is tangent to the z-axis. O (x - 8)3 + (1 - 3)2 = 3 O (2 +8)3 + (y + 3)2 =9 O (2 - 8)2 + (y - 3)2 = 9 O (x +8)2 + (# + 3)3 =3What is the equation of the given ellipse? (1, 4) (4, 2) O (2 - 1) + (y-2)3 2 - = 1 ( 2+1)2 (y+2)3 9 4 - =1 O (-1) (y-2)2 3 2 - =1 O (*-1)' (y-2)' 9 = 18 of 19 The point (4, k) lies on the ellipse + =1. 32 18 Which of the following could be a value for k? O 3/2 0 6 0 3 0 9QUHB An ellipse has centre {0.0) and vertices en the zaxis. The miner axis has length 8 and the major axis has length 18. Find the equation of the ellipse. O z + i = 1 0\"\" i\