1 of 21 This question has two parts. First, answer Part A. Then, answer Part B. Use the graph to answer both parts. Item 1 Item 2 Item 3 2 Item 4 Item 5 1- Item 6 -2 2 3 Item 7 -1 Item 8 -2 -3 Part A Given the function f (z) plotted in the graph, which of the following limits has a value of 2? (1 point) lim f (I) lim f (I) z-10+ lim f (I) O lim f (I) O lim f (I) Use the graph to answer the question. Which is the graph of the derivative? (1 point) Suppose f (I) = ' + 2x-1, r1 (1 point) O a= -2, b=4 O a =-1, b=3 Oa=1, b=1 O a =2, b=0 O a =3, b=-1Suppose you are given a funcon f (3) where f(2) = 5 and f' [2) = 2 What is the equation of the line that is perpendicular to the graph of f[;|:} at x= 2? {pr'nt} (1:: y=%+4 Q y=7z a] y: z+4 Pt; Part B Based on the graph of f (x), what is lim f (x)? (1 point) 0 1 O 2 O 3 O The limit does not exist.What is the equation of the line tangent to the graph of f (x) = va at the point x = 1? (1 point) Oy= I+ O y= - I+ O y= 1 O y= + O y= IWhat is the slope of the line tangent to the graph of f (x) = sin (x) at x = "? (1 point) O m= O m= V2 O m= 1 O m = v2 O m = 2This question has two parts. Part A The position of an object bobbing up and down on a spring is given by the function s = 3 + sint, where s is in feet and t is in seconds. What is the velocity of the object in terms of t? (1 point) O v= 3 + - cost inches per second O v = 3 - sin t inches per second O v = - -sint inches per second O v = - -cost inches per second O v= = cost inches per second Part B What is the jerk experienced by the object at t = # seconds? (1 point) O _ 3v2 inches per second cubed O -= inches per second cubed 3v3 inches per second cubed O Bv2 inches per second cubed O - inches per second cubedThe height of an object launched vertically upward is given by the function h (t) = 200 + 11t - 4.9t, where h is in meters and t is in seconds. What is the object's approximate speed when it hits the ground?? (1 point) O -199.42 meters per second O -85.48 meters per second O -63.48 meters per second 63.48 meters per second O 85.48 meters per secondEstimate the limit numerically: lim -1 I-+0 (1 point) 0 -2 0 -1 OO O 1 O2What is lim (1 point) 0 -00 32 OO 04What is lim x 451-451-2 7+-2 (1 point) O -3 0 -2 O2 O undefinedWhat is the horizontal asymptote of y = 32 Cos I-51. (1 point) O y=-4 O y= -2.5 Oy=-1 O y=0 O There is no horizontal asymptote.What is lim I-+-00 (1 point) O -00 O OFor what value of a is f (x) continuous? x +1, f (I) = 12 - 2r +a, 1>3 (1 point) O -2 0-1 0 1 0 4