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1 ) Phosphine can be decomposed at 1 . 0 atm. pressure according to the equation 4 PH 3 - > P 4 + 6

1) Phosphine can be decomposed at 1.0 atm. pressure according to the equation
4PH3->P4+6H2
The reaction takes place in a tubular reactor in which 80% of the phosphine feed is
converted. If pure phosphine is fed to the reactor at 680oC and a rate of 2.5 kmol h-1
evaluate
a) the heat load on the reactor assuming isothermal operation
b) the gas exit temperature assuming adiabatic operation
Data Enthalpy of reaction =23.71 kJ mol-1 phosphine converted at 298 K
Mean specific heat capacities between 298K and 1000 in J mol-1 K
-1
:

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