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(1 point) (a) Graph r = 1/(8 cos () for -7/2 (1 point) (a) Graph r = 1/(8 cos 0) for n/2 9 n/2 and

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(1 point) (a) Graph r = 1/(8 cos () for -7/2

(1 point) (a) Graph r = 1/(8 cos 0) for n/2 9 n/2 and r = 1. Then write an iterated integral in polar coordinates representing the area inside the curve r = 1 and to the right of r = 1/(8 cos 0). (Use t for 9 in your work.) With a = , and d = d (b) Evaluate your integral to find the area. area = d

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