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(1 point) Consider the function f(x) = x3 - 5x2 + 9r - 1. (a) f is concave up for r E (b) f is
(1 point) Consider the function f(x) = x3 - 5x2 + 9r - 1. (a) f is concave up for r E (b) f is concave down for T E (c) The inflection points of f occur at r =(1 point) Consider the function f(x) = xe13x (a) f is concave up for I E (b) f is concave down for T E (c) The inflection points of f occur at r =1 (1 point) Consider the function f(I) = 6:x2 + 2 (a) f is concave up for r E (b) f is concave down for r E (c) The inflection points of f occur at r =(1 point) Consider the function f(x) = 4(x - 3)2/3 (a) Find all critical numbers c of f. c = (b) f is increasing for T E (c) f is decreasing for T E (d) f is concave up for I E (e) f is concave down for E(1 point) Consider the function f(r) = 82 - 6x4. (a) Find all critical numbers c of f. C= (b) f is concave up for I E (c) f is concave down for r E (d) Using the 2nd derivative test, the local maxima of f occur at x = (e) Using the 2nd derivative test, the local minima of f occur at r =(1 point) Consider the function f(r) = & + 9 (a) Find all critical numbers c of f. C = (b) f is concave up for T E (c) f is concave down for T E (d) Using the 2nd derivative test, the local maxima of f occur at x = (e) Using the 2nd derivative test, the local minima of f occur at r =(1 point) Consider the function f(I) = (a) f' (x) = (b) f is increasing for I E (c) f is decreasing for I E (d) The local minima of f occur at c = (e) The local maxima of f occur at c = (1) f" (I) = (g) f is concave up for I E (h) f is concave down for I E (i) The inflection points of f occur at c ={1 point]: Let x) be the function show in the graph below. Click on the graph to enlarge it. {a} State the point at which 3'" has an absolute minimum: { {b} State the point at which f has an absolute maximum: { {c} Complete each of the following statements: {i} The function attains a local '3 v at a = 2. (ii) The function attains a local '2 v at a: = 4. {iii} The function attains a local ? v at I = 5. (1 point) Suppose f(r) = re 0
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