(1 point) Consider the surface F(;v, y, z) : 3:827 + sin(yz7) + 6 : 0. Find the following partial derivatives % = 8x"72"7 & : By (1 point) Use the chain rule to find dz d+ . where z = xytay', x=-4+t, y=-3-+4 First the pieces: az 2 xy+y12 Ox Oz x^2+2xy ay = 6t15 dt dy -4t^3 dt End result (in terms of just t): dz dt(1 point) Given 2 2 x, 3}), a: = 33(u, v), y = y(u,v), with 23(1, 0) = 3 and 9(1, 0) = 1, calculate zu(1, 0) in terms of some of the values given in the table below. zu(1, 0) : dc