(1 point) Find an equation for the plane through the points (3, 3, 3), (1, -1, 0), (-2, 0, 2). The plane is(1 point) Find the distance the point P(-6, 9, 3), is to the plane through the three points Q(-5, 5, 0), R(-10, 6, -1), and S(-7, 1, -1).(1 point) Find the distance of the point (2, 5, -5) from the line r() = (1 + 3t, -1 + 31,5 -3t). Answer:{1 point} Determine whether the lines Ll :x=6+!, y=9+31, z=14+31 and L2 : x: 1 +2: 3;: 10+51' z= ?+! intersect. are skew. or are parallel. it they intersect, determine the point Of intersection; if not leave the remaining answer blanks empty. Dolare the lines: ? v Point of intersection: { . . 1' (1 point) Find the intersection of the lines r() = (0 - 21, 11 + 4t, 14 + 8:) and R(s) = (17 + 7s, -5 - 5s, 4 + s). Write your answer as a point (a, b, c) where a, b, and c are numbers. Answer: Note: If there is no intersection, write "none"