(1 point) Find an equation of the line that is tangent to the graph of y(x) = 3111(2 + x2) at x = -4 . Equation of the tangent line is y= -7.60845x-30.4338 (1 point) Find the local linear approximation of the function f (x) = V2 + x at x0 = 23, and use it to approximate \\/24.9 and V251. (a) at) = V2 + x z 5+1/10(x23) (b) \\/24.9 m (c) 25.1 m 3.180624594 For parts (b) and (c), you should enter your answer as a fraction. If you enter a decimal, make sure that it is correct to at least six decimal places. (1 point) Use linear approximation, i.e. the tangent line, to approximate as follows: Let f (x) = ' 1 equation of the tangent line to f (x) at a "nice" point near 0.253. Then use this to approximate m. 1 and find the x (1 point) Use linear approximation, i.e. the tangent line, to approximate 2.86 as follows: Let f(x) = x6. The equation of the tangent line to f(x) at x = 3 can be written in the form y = mx + b where m is: and where b is: Using this, we find our approximation for 2.86 is