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(1 point) Find an equation of the tangent to the curve given by x = tan(0), y = sec(0) at the point (x, y) =

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(1 point) Find an equation of the tangent to the curve given by x = tan(0), y = sec(0) at the point (x, y) = (1, v2). Your answer should be in the form of y = f (ac ) without 0. y(x) =

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