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(1 point) Find the equation for the line tangent to the parametric curve: X = t3 16t y = 16+2 - +4 at the
(1 point) Find the equation for the line tangent to the parametric curve: X = t3 16t y = 16+2 - +4 at the points where t = 4 and t = 4. For t = 4, the tangent line (in form y = mx + b) is = Fort-4, the tangent line is y =
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