(1 point) Find the equation of a plane that is perpendicular to the vector i - j - 2 k and passing through the point (-4, 4, -4). The plane is given by:(1 point) The plane that passes through the point (-2, -3, -3) and is perpendicular to both 2x - 2y - 3z = 10 and x - 5y - 3z = -16 has as its implicit equation. Hint:{1 point} Find a nonzero vector parallel to the line of intersection of the two planes 3:: + y + z = 3 and 3x 4y 52 = l. \f(1 point) Find a vector equation with parameter : for the line of intersection of the planes x + y + z = 9 and x + z = 0. Answer: r(t) =