(1 point) If the joint density function of Xand Yis (,)=(22)5, f ( x , y ) = c ( x 2 y 2 ) e 5 x , with 00 Y = y > 0 . Conditional density |(,)= f X | Y ( x , y ) =12.5(x2y2)e5x e5y(y+ 1 5)(Enter your answer as a function of x , with yas a parameter.)(b) The conditional probability distribution of Y , given = X = x . Conditional distribution |(|)= F Y | X ( y | x ) =(for x y x ). (Enter your answer as a function of y , with xas a parameter.)

(1 point) If the joint density function of X and Y is with 0 S x 0. Conditional density f X|y(X, y) = (Enter your answer as a function of x, with y as a parameter.) (b) The conditional probability distribution of Y, given X = x. Conditional distribution FY|X(y|x) = C] (for x S y S x). (Enter your answer as a function of y, with x as a parameter.) f(x, Y) = 0062 - y2)e_5x