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1 point) Suppose a parabola has its axis of symmetry at x = 12, has a vertical stretch of 3, opens downward, and has its

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1 point) Suppose a parabola has its axis of symmetry at x = 12, has a vertical stretch of 3, opens downward, and has its vertex at the point (12, -1)? What is a formula for the parabola in standard form f(x) = ax + bx + c? Enter the values of a, b, and c in the appropriate places. f(x) = I' + r+ Preview My Answers Submit Answers You have attempted this problem 0 times. You have 6 attempts remaining

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