(1 point) The nicotine content in cigarettes of a certain brand is normally distributed with mean (in milligrams) / and standard deviation o = 0.1. The brand advertises that the mean nicotine content of their cigarettes is 1.5 mg. Now, suppose a reporter wants to test whether the mean nicotine content is actually higher than advertised. He takes measurements from a SRS of 10 cigarettes of this brand. The sample yields an average of 1.4 mg of nicotine. Conduct a test using a significance level of a = 0.05. (a) The test statistic 1.956 (b) The critical value, z* = 1.645 (Hint: The critical value should be one of the following values: -2.33, -1.645, 1.645, 2.33) (c) The final conclusion is A. There is not sufficient evidence to show that the ad is misleading. OB. The nicotine content is probably higher than advertised. Note: You can earn partial credit on this problem. Preview My Answers Submit Answers You have attempted this problem 15 times. Your overall recorded score is 67%. You have unlimited attempts remaining. Email instructor(1 point) According to a recent marketing campaign, drinkers of either Diet Coke or Diet Pepsi participated in blind taste tests to see which of the drinks was their favorite. In one Pepsi television commercial, an anouncer states that "in recent blind taste tests, at least one half of the surveyed preferred Diet Pepsi over Diet Coke." Suppose that in one of those taste tests, 49 out of the 110 participating preferred Diet Pepsi. Test the hypothesis, using o = 0.01 that at least half of all participants will select Diet Pepsi in a blind taste (hint: take H. to be that fewer than half prefer Diet Pepsi) test by giving the following: (a) the test statistic -1.37 Recall the z value that marks the start of the rejection region is the critical z score; if you're lower tailed, it's the z value that has left area of a; if you're right tailed, it's the z value whose area to the right is or; if you're two-tailed, they're the values of the :z value that -z has left area of " and z has a right are of , ... note the divided by 2 part! (b) the critical z score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p = 0.5. B. We can reject the null hypothesis that p = 0.5 and accept that p