(1 point) Use the Squeeze Theorem to evaluate the limit ling f(a3), if 31) 12a: 36 3 at) 3 3:2 on [4, 8]. Enter DNE if the limit does not exist. Limit = (1 point) Evaluate m f(3 + h) f(3) h>0 h a where f(;13) = |$ 3| 6. If the limit does not exist enter -1000. Limit = (1 point) Consider the following limit , 112 8:1: |z122 14ml 11m w>8 |$2 196| 132 We can simplify this limit by rewriting it as an expression without absolute values as follows limit>8 We can then cancel off a common factor in the numerator and denominator, thus simplifying our limit to hmm>8 We can then evaluate the limit directly and find that its value is (1 point) Consider the functions W 2:: and 9&3): 0 0S3" 10 :138 . lim 9(113) : 0, and arr>8 What can be said about the relative sizes of f(a:) and g(:1:) as a: approaches 8? Select all that apply. C] A. Values of ux) are about 5 times as large as values of 9(33) as a: approaches 8. C] B. g(a3) % 5f($) for a: near 8. C] C. Values of g(a:) are about 5 times as large as values of f(a3) as a: approaches 8. C] D. f(:c) % 59(3)) for :1\"; near 8. C] E. Nothing definitive can be said. (1 point) Let f be defined by f (ac) = 2x3 - 2m, 20 5 - 1 6x2 + 5m , x > -1 (a) Find (in terms of m) lim f(x) x->- 1+ Limit = (b) Find (in terms of m) lim f(x) Limit = (c) Find the value of m so that lim f(x) = lim f(x) m =(1 point) Evaluate the limits. 5x f ( 20 ) = OC = Enter DNE if the limit does not exist. a) lim f(x) = x-0 b) lim f(a) = c) lim f (x) = x-0 d) f(0) =(1 point) a. choose If lim f(x) = 5, then lim f(ac) = 5. x-1- x-+1 b. choose v If lim f(x) = 5, then lim f(x) = 5. x-1 x -1+ C. choose v If lim f(x) - 5, then lim f(x) = 5. x-1 x-1 d. choose If lim f(x) = 5, then lim f(ac) = 5. x-1 x-1+ e. Select all true statements. Assume that all the limits are all taken at the same point. O A. If the two-sided limit exists, then the left- and right-hand limits both exist and are equal. O B. If the right-hand limit exists, then the two-sided limit exists. O C. If the left- and right-hand limits both exist and are equal, then the two-sided limit exists. O D. If the left-hand limit exists, then the two-sided limit exists.(1 point) If lim f( ac = -7, then x-3 2 - 3 4 lim f(x) = x-3