(1 point} Using the method of substitution, 1:] 31(1+2$2}2d$=f f[u)du where do. 2 d2: ft\") = Using the above information: f 31(1 | 22:2)2d1: = f Hulda : (in terms of u} = (in terms of 2:) Note: Don't forget the constant of integration in the last two blanks