1. Prove that the elevation of CoG of a jumper is given as a. hTOP=2gy2pushorf b. hIM=8gT2tot, where g is the acceleration due to gravity, Ttot is the difference between the instant of landing and the instant of take-off, and vpushoff is the velocity of CoG at the end of push-off phase (take initial velocity of jumper v= 0). 2. According to The Guinness Book of World Records, 14th edn (1976), the world record was held by Johan Christian Evandt (Norway, 1962) who cleared a bar 5 feet 921 inches (1.76m) off the ground! What average push-off force, Fequiv was exerted during this jump? (Take the jumper's height to be 6 feet, so that his center of gravity was 36 inches off the ground at the end of push-off. We will also assume that during the jump he oriented his body so his center of gravity just cleared the bar, so the total net elevation of his center of gravity was h=69.536 inches =33.5 inches. Also note that a typical crouch distance for a 6 foot tall person is 20 inches)