1 Question 100% Attempt The density of water is 1.00 x 10' kg/m, and the density of mercury is 1.36 x 104 kg/m . 2 Question of co Attempts Macmillan Learning Calculate the absolute pressure pb at the bottom of a 0.250-m Question 0% tall graduated cylinder that is one-fourth full of mercury and Pb = of go Attempts three-fourths full of water. 4 Question 0/100 .0 of co Attempts 5 Question 0% 2 of co Attempts 6 Question 0% 0 of co Attempts np . . .. .... .... . . .. . . .." . ..'. . . pre sc 144 DI insert ese ? 12 2 a # % &Water, with a density of p = 1185 kg/m', flows in a horizontal pipe. In one segment of the pipe, the flow speed is 0% 01 = 7.53 m/s. In a second segment, the flow speed is U2 = 2.77 m/s. What is the difference between the pressure in the seco mots segment ( P2) and the pressure in the first segment (P1)? Macmillan Learning lestion 0% tempts -28759.35 P2 - P1 = Pa Question 0% of so Attempts Incorrect 45 Question 0/100 2of Attempts 6 Question 0% foo Attempts hp ..... . .... .. . . . . . . . .. . . . . . . . . . . . .. . . . . . . . . . . . .. . . insert prt sc delete 4- 144 0 DII DDI esc ? backspace rome # $ % 2 3 4 5 6Question 6 of 6 > A platinum sphere with radius 1.63 cm is totally immersed in mercury. Find the weight of the sphere, the buoyant force acting on the sphere, and the sphere's apparent weight. The densities of platinum and mercury are 2.14 x 10* kg/m and 1.36 x 10# kg/m', respectively. Macmillan Learning weight: N buoyant force: N apparent weight: N hpQuestion 5 of 5 > Attem A baseball of mass 0.145 kg is thrown at a speed of 39.0 m/s. The batter strikes the ball with a force of 24,000 N. The bat ar ball are in contact for 0.500 ms. Macmillan Learning Assuming that the force is exactly opposite to the original rect direction of the ball, determine the final speed of of the ball. I Uf = 100% Correct * TOOLS X10 0% b Search hp 144 DDI 112 7 insert prt sc delete 15 - BRACE 16 40 4- + esc ? K home # . $ % & backspace @ 2 4 5 6 U P L g up Q W E R T enter pg dn K A S D F G H pause T shift endA diver is 29.0 m below the surface of the ocean. The surface pressure is 1.00 atm, and the density of seawater is 1.02 x 10' kg/m. Macmillan Learning What is the absolute pressure p experienced by the diver? P = % What is the gauge pressure gauge experienced by the diver? Pgauge 100% Correct 66.7% 12:42 PM 10/17/2023 Q Search . . . . . . . . . . . .. .. .. . . . . . . . . . . . a .. . . .. ..a . . . .... . .. . . . ... . .. . . . .. . . .. . . . .. . . .. . . . . . . . . . .... . . . . . . . . . . . . . . . . . . . . . 6 1- 18 12 delete 144 10 71 DDI nsent ort sc # Z $ & home 4 5 6 8 O backspace@ Assignment Score: 69.4% Resources CX Give Up? Feedback Resume RX Ky Question 4 of 6 > At empt 1 The density of water is 1.00 x 105 kg/m', and the density of mercury is 1.36 x 10* kg/m3. Macmillan Learning Calculate the absolute pressure pb at the bottom of a 0.250-m tall graduated cylinder that is one-fourth full of mercury and 10.177875 x10 three-fourths full of water. Pb Incorrect I'm ect 6.7% 12:45 PM 10/17/2023 Q Search hp . . . . . . . . . . ." . .. . .. . . ... . . . . . . ... . . . . ... .. ... . . .. . . . . . . . ". . . . . .'' . . . . . . . . . . . . . . . ' .' . . . . . .' ::... . . . . . . . . . . . . . . . . . delete 171 DDI nsert prt sc 19 Attempt2 A platinum sphere with radius 1.63 cm is totally immersed in mercury. Find the weight of the sphere, the buoyant force actit on the sphere, and the sphere's apparent weight. The densities of platinum and mercury are 2.14 x 104 kg/m and 1.36 x 10* kg/m', respectively. Macmillan Learning weight: 3.806 0% 100% 0.419 Correct buoyant force: Incorrect 66.7% D 12:45 PM 10/17/2023 Q Search hp ". . . . . . . . . . . .... . . . prt sc delete 12 insert 19 144 DII 71 DDI 5 . 16 4- 12 4 10 ? backspace home & O # . $ % 3 4 5 6 8 pg up PQ D) Oi= - 3gulls 0. 145 ( V- (- 39) ) - 24,000 V = 143- 758 wills pressure at the depth f zom Pgh = (1 02 ) xto3 x 9. 84 x2g 2 289884 Pa Absolute pressure = Palm + Page 1: 01 X 105 + 2. 898 X805 - 2:908 3908 84 PaDate DELTA Pg No. pres ( gauge) at bottom . 1 - = (1. 36 x 104 ) X 9-8 x1. (0. 250) + (1050) (9 8)1, 3 ( 025)) 8330 + + 837-5 2 10167 . 5 Pa Pabsolute ? paton + Pb = 1 . OLX105 + + 0167 - 5 Pa = +1 1 167 -5 Pa 20 volume 2 * ( 3 - 14 ) ( 0 01 6 3) 3 = 1 . 81 3 x165 m ] weight ? () ( d opt x q (1 . 813 X105) ( 2-14 x204) (0-8 ) = 3. 802N FB ( ) (d )mercury x 2 2 2.4+6 N Apparent weight = W -FB = 4. 386 N