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1. Solve linear programming problem min{x12x2+x3+x42x5x6+3x7x8} subject to 2x1x2+x3x4x5+2x6+x8=4,x12x2x3+x42x52x6x8=7,x1x3+2x5+x6x7+x8=0,x2+x4+2x5+x72x8=5,xj0,j=1,,8. Starting point x0=17103435347117303419346334633413. Tolerance =0.001. Give as the answer the obtained point, objective function value, and
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