Question
1 Suppose in a test of hypothesis the probability value (p-value) is 0.0725. Then you should, a reject H at = 0.10, but not reject
1 Suppose in a test of hypothesis the probability value (p-value) is 0.0725. Then you should,
a reject H at = 0.10, but not reject H at = 0.05.
b reject H at = 0.05, but not reject H at = 0.10.
c not reject H at = 0.10.
d reject H at = 0.05.
2 You are asked to perform a hypothesis test that population mean is greater than 80. Which of the following is the correct statement of the null and alternative hypotheses for this test?
a H: > 80 H: 80
b H: 80 H: < 80
c H: 80 H: > 80
d H: 80 H: > 80
3 You are asked to perform a hypothesis test that population mean is at most, or no greater than, 65. Which of the following is the correct statement of the null and alternative hypotheses for this test?
a H: < 65 H: 65
b H: 65 H: < 65
c H: 65 H: > 65
d H: > 65 H: 65
4 You are asked to perform a hypothesis test that population proportion is at least, or no less than, 0.65. Which of the following is the correct statement of the null and alternative hypotheses for this test?
a H: 0.65 H: < 0.65
b H: 0.65 H: > 0.65
c H: > 0.65 H: 0.65
d H: < 0.65 H: 0.65
5 You are asked to perform a hypothesis test that population proportion is different from 0.35. Which of the following is the correct statement of the null and alternative hypotheses for this test?
a H: 0.35 H: = 0.35
b H: = 0.35 H: 0.35
c H: 0.35 H: < 0.35
d H: 0.35 H: > 0.35
6 Which of the following statements about Type I and Type II errors is correct:
A Type I: Reject a true alternative hypothesis. Type II: Do not reject a false alternative.
B Type I: Reject a false null hypothesis. Type II: Reject a true null hypothesis.
C Type I: Reject a true null hypothesis. Type II: Do not reject a false null hypothesis.
D Type I: Do not reject a false null hypothesis. Type II: Reject a true null hypothesis.
7 In a test of hypothesis, the symbol represents:
A The power of the test, or the probability of rejecting a false H.
B The level of significance, or the probability of not rejecting a false H.
C The level of significance, or the probability of committing a Type II error.
D The level of significance, or the probability of rejecting a true H.
Questions 8-12 are related to the following:
Consider the following hypothesis test.
H: 120
H: < 120
8 This test is:
a A lower-tail test.
b An upper-tail test.
c A two-tail test.
d A closed-interval test.
You obtain the following random sample to test the hypothesis in the previous question.
154 118 94 102 157 113 124 115 140
105 125 103 87 95 105 134 133 137
169 135 125 100 130 127 144 122 128
63 101 80 153 82 166 156 101 123
118 133 133 144 114 121 122 133 110
110 134 130 120 79 120 98 173 66
129 116 99 99 92 107 129 75 109
104 148 140 138 119 121 90 131 55
143 92 109 98 159 138 129 169 95
92 118 151 138 120 148 110 103 130
114 58 138 135 92 117 114 123 94
124 108 132 118 121 104 155 89 96
106 123 116 123 85 95 97 96 95
111 136 103 88 109 122 103 128 162
98 97 152 131 72 141 130 128 116
92 123 146 135 114 116 104 97 120
93 70 77 90 131 91 137 85 144
9 The test statistic is, |TS| = _______
a 2.004
b 1.890
c 1.783
d 1.682
10 The critical value for a 5 percent level of significance is:
a 1.655
b 1.761
c 1.873
d 1.993
11 The p-value for the test is,
a 0.0982
b 0.0546
c 0.0303
d 0.0168
12 The test leads you to:
a Reject H at a 10 percent, but do not reject H at a 5 percent level of significance.
b Reject H at a 10 percent, and reject H at a 5 percent level of significance.
c Do not reject H at a 10 percent level of significance.
d Do not reject H at a 5 percent level of significance.
Questions 13-15 are based on the following
American workers spend an average of 50 minutes to and from work in a typical day.
You obtain the following random sample of commuting time of employed adults in Indianapolis metropolitan area (IMA) to test the hypothesis below:
67 41 67 44 42 31 28 65 49
65 33 53 16 46 45 49 54 46
61 87 40 33 35 46 51 67 49
56 51 47 59 51 77 53 63 47
55 58 46 43 36 76 44 36 30
38 69 48 9 52 56 72 40 72
43 46 37 73 50 43 12 55 49
82 44 45 46 59 49 40 43 41
48 39 29 45 40 70 2 29 42
56 51 67 37 37 36 37 43 64
34 56 40 47 52 64 59 65 60
54 16 36 47 43 32 41 31 51
Is there enough evidence, at = 0.05, to conclude that the average commuting time in IMA is less than the national average?
13 To perform a hypothesis test, the null and alternative hypotheses for this test are:
a H: < 50 H: 50
b H: > 50 H: 50
c H: 50 H: < 50
d H: 50 H: > 50
14 For the previous question, the test statistic is |TS| = _______.
a 1.941 Reject H.Conclude the average commuting time in IMA is less than the national average.
b 1.941 DNR H.Do not conclude the average commuting time in IMA is less than the national average.
c 1.617 Reject H.Conclude the average commuting time in IMA is less than the national average..
d 1.617 DNR H.Do not conclude the average commuting time in IMA is less than the national average.
15 In the previous question the p-value = ______.
a 0.0979
b 0.0544
c 0.0302
d 0.0168
16 The expected fill of bottles of a beverage filled in a bottling plant is 750 milliliters (ml).
You obtain the following random sample of filled bottles.
750.07 748.95 750.09 750.03
750.34 750.11 749.19 748.26
749.03 749.71 749.73 749.13
750.6 749.41 750.19 749.42
750.24 749.09 749.08 751.45
Does the sample provide significant evidence that the mean fill is different from the expected fill? Compute the test statistic (TS) and the critical value at the 5% level of significance.
TS CV
a 2.541 2.721 Do not conclude the mean fill is different from the expected fill.
b 2.541 2.093 Conclude the mean fill is different from the expected fill.
c 1.815 2.093 Do not conclude the mean fill is different from the expected fill.
d 1.815 1.645 Conclude the mean fill is different from the expected fill.
Sample data | ||||||||||||||||||||||
1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | |
0 | 0 | 1 | 1 | 0 | 0 | 1 | 1 | 1 | 0 | 0 | 0 | 1 | 0 | 1 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | |
1 | 0 | 1 | 1 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 1 | 1 | 0 | 1 | 0 | 1 | |
1 | 1 | 0 | 0 | 0 | 1 | 1 | 0 | 0 | 1 | 1 | 0 | 1 | 1 | 1 | 0 | 0 | 1 | 1 | 1 | 0 | 0 | |
1 | 0 | 0 | 1 | 1 | 1 | 0 | 1 | 0 | 1 | 1 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | |
1 | 0 | 0 | 0 | 1 | 1 | 0 | 0 | 1 | 1 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 1 | 0 | 1 | 0 | 0 | |
0 | 1 | 1 | 0 | 1 | 0 | 0 | 1 | 1 | 0 | 1 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | |
1 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 0 | 1 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | |
0 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | 0 | 0 | 1 | 0 | 0 | 0 | 1 | 1 | 0 | 0 | |
0 | 1 | 0 | 1 | 1 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 0 | |
0 | 0 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 1 | 1 | 1 | 0 | 1 | 0 | 0 | 1 | 1 | 1 | 1 | 1 | |
0 | 0 | 1 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 1 | 0 | 1 | 0 | 1 | 0 | |
1 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 1 | 0 | |
0 | 0 | 1 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 1 | 1 | |
0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 1 | 0 | 1 | 1 | 0 | 0 | 1 | 0 | 1 | 0 | 0 | 1 | |
1 | 0 | 0 | 0 | 1 | 0 | 1 | 1 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | 1 | 1 | 0 | |
0 | 1 | 0 | 0 | 1 | 1 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 0 | 0 | 1 | |
0 | 1 | 0 | 1 | 1 | 0 | 0 | 1 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | |
1 | 0 | 1 | 0 | 1 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 1 | 1 | 0 | 1 | 0 | 0 | 1 | 1 | 1 | |
1 | 1 | 0 | 1 | 0 | 1 | 1 | 0 | 1 | 1 | 0 | 0 | 1 | 1 | 0 | 1 | 0 | 0 | 1 | 1 | 1 | 1 | |
0 | 0 | 1 | 0 | 1 | 1 | 0 | 1 | 1 | 0 | 1 | 0 | 1 | 0 | 1 | 0 | 1 | 0 | 1 | 0 | 0 | 1 | |
0 | 0 | 1 | 0 | 0 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | |
1 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | |
0 | 1 | 0 | 0 | 1 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 1 | 1 | 0 | 1 | 0 | |
0 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | |
1 | 0 | 1 | 0 | 0 | 0 | 1 | 1 | 1 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 1 | 1 | 1 | 1 | |
1 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 1 | 0 | 1 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 0 | 1 | |
0 | 1 | 0 | 1 | 0 | 0 | 0 | 1 | 0 | 1 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | |
1 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | |
1 | 1 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 0 | 0 | 1 | 1 | 1 | 1 | |
0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | 0 | 1 | 1 | 1 | 0 | |
1 | 0 | 0 | 0 | 1 | 0 | 1 | 1 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 0 | |
1 | 1 | 0 | 0 | 1 | 0 | 1 | 1 | 1 | 0 | 1 | 1 | 0 | 1 | 1 | 0 | 0 | 1 | 0 | 1 | 0 | 1 |
Questions 17 and 20 are related
The national obesity statistics indicates that 41 percent of American adults is obese.
To test the hypothesis thatthe percentage of Indiana adults who are obese is greater than the national rate of obesity the following random sample is obtained.
In the binary sample data "1" indicates that the person is obese and "0" not obese.
17 The fraction of the persons in the sample who are obese is p = _______
a 0.470
b 0.459
c 0.448
d 0.437
18 The standard error of the sample proportion is ______
a 0.0183
b 0.0207
c 0.0236
d 0.0268
19 Does the sample provide significant evidence that the obesity rate in Indiana is higher than the national rate? State the null and alternative hypotheses:
a H: 0.41 H: < 0.41
b H: 0.41 H: > 0.41
c H: > 0.41 H: 0.41
d H: < 0.41 H: 0.41
20 Use a 5% level of significance for the hypothesis test in the previous question. P-value for this test is ______.
a 0.1047 Reject H.Conclude the Indiana obesity rate is higher than the national rate.
b 0.1047 DNR H.Do not conclude the Indiana obesity rate is higher than the national rate.
c 0.0722 Reject H.Conclude the Indiana obesity rate is higher than the national rate.
d 0.0722 DNR H.Do not conclude the Indiana obesity rate is higher than the national rate.
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