1. take your time

(c) Estimate the proportion of stay-athome residents in Virginia. (Round your answer to four decimal places.) Does this proportion differ significantly from the mean proportion for all states? Use a = 0.05. Find the value of the test statistic. (Round your answer to two decimal places.) 2.245 ./ Find the pvalue. (Round your answer to four decimal places.) p-value = 0.0251 '/ What is your conclusion? 0 Do not reject H0. There is insufficient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577. O Reject H0. There is sufficient evidence to conclude that the proportion of stay-athome residents in Virginia differs from the overall proportion of 0.577. O Reject H0. There is insufcient evidence to conclude that the proportion of stay-at-home residents in Virginia differs from the overall proportion of 0.577. Do not reject H0. There is sufcient evidence to conclude that the proportion of stayat-home residents in Virginia differs from the overall proportion of 0.577. K (d) Would you expect the proportion of stay-at-home residents to be higher in Virginia than in Arkansas? Support your conclusion with the results obtained in parts (b) and (c). From the results obtained in parts (b) and (c), we would expect the number of stay-at-home residents to be: _:x in Arkansas than Virginia. The sample results show that, rounded to two decimal places, the estimated percentage of Arkansas residents who were born there is :] %. TH ults also show that, rounded to two decimal places, the estimated percentage of Virginia residents who were born there is :] \"/0. What percentage of the population live in their state of birth? According to the U.S. Census Bureau's 2014 American Community Survey, the gure ranges from 25% in Nevada to 78.7% in Louisiana. The average percentage across all states and the District of Columbia is 57.7%. The data in the le HomeState are consistent with the ndings in this American Community Survey. The data are for a random sampe of 120 Arkansas residents and for a random sample of 180 Virginia residents. (a) Formulate hypotheses that can be used to determine whether the percentage of stay-at-home residents in the two states differs from the overall average of 57.7%. O HO: p > 0.577 Ha: p S 0.577 H0: ,0 = 0.577 Ha: p z 0.577 O H0: ,0 2 0.577 H3: p 0.577 V (b) Estimate the proportion of stayathome residents in Arkansas. (Round your answer to four decimal places.) 0.6167 Does this proportion differ significantly from the mean proportion for all states? Use a = 0.05. Find the value of the test statistic. (Round your answer to two decimal places.) 0.88 ., Find the p-value. (Round your answer to four decimal places.) p-value = 0.3877 X What is your conclusion? O Reject H0. There is insufcient evidence to conclude that the proportion of stayathome residents in Arkansas differs from the overall proportion of 0.577. Q) Do not reject H0. There is sufcient evidence to conclude that the proportion of stay-athome residents in Arkansas differs from the overall proportion of 0.577. O Reject H0. There is sufficient evidence to conclude that the proportion of stay-athome residents in Arkansas differs from the overall proportion of 0.577. O Do not reject H0. There is insufficient evidence to conclude that the proportion of stay-at-home residents in Arkansas differs from the overall proportion of 0.577