1) The force of gravity A) The force of gravity near the surface of the earth is given by F=mg, where m is the mass and g is the gravitational acceleration vector. What is the force of gravity for a 1) The force of gravity A) The force of gravity near the surface of the earth is given by F=mg, where m is the mass and g is the gravitational acceleration vector. What is the force of gravity for a 10 kg, 20kg, 100 kg projectile? Since, force is a vector your answer should include a direction (for example toward the moon). If you want you can use a coordinate system, but you will need to define your coordinate system first. Again, force is a vector, so to get this right you have to include magnitude and direction. Draw the free body diagram (FBD) for each projectile. A FBD is diagram that helps us with a force analysis. To make a FBD, model the object of interest as a point. Draw arrows for each force on the object. The length of the arrow indicates the magnitude of the force, the direction of the arrow indicates the direction of the force. (Hint, all your diagrams will be different.) B) For each of the masses in part A what is the acceleration? Acceleration is a vector, so you answer should have a direction.To find this consider Newton's second law F=ma. In this case the relevant force is mg. (This is not very complicated, you will get the answer you expect.) C) So far we have only considered gravity near the surface of the Earth. Newton's law for gravity describes the gravitational attraction between two objects. This is the more general way to calculate the gravitational force (not just for cases near the surface of the Earth). The magnitude of the gravitational force between two obiects isF=G(m1m2/r^2), where m_1 is the mass of object 1, m_2 is the mass of object 2, r is the distance between the two objects, and G is Newton's gravitational constant, G=6.6710^-11N m^2/kg^2. Let us consider the force of gravity between you and the Earth. Let m 1 be the mass of the Earth which we will denote as M_E. Let m_2 be your mass, which we will denote as m. And r be the radius of Earth (the distance from the center of the Earth to the surface, where you are standing), which we will denote as R_E. Since F = ma, show that the acceleration (in magnitude) you experience at the surface of the Earth is a=G(M E/R^2 E) Compute this value with the numerical values of G, M_E and R_E. What do you get? D)Suppose instead of standing at the surface of the Earth you were in a building 100 meters high. You could compute the acceleration due to gravity you experience in just the same way, but instead of using R_E as the distance, you would use R_E + 100 m.In this case what is your acceleration (in magnitude). What is the point I am trying to make with this problem? E)Near the surface of the Moon, the acceleration due to gravity is not 9.8 m/s^2 down. The moon is less massive than the earth, so the acceleration is not as strong. Below are two plots of the vertical velocity of a projectile. One plot is for a projectile on Earth. The other is for a projectile on the Moon.Which one is projectile on the Moon (blue or orange)? Explain your answer.From the plot determine the acceleration due to gravity for the Moon. F) Compute the acceleration of gravity near the Moon's surface using the same method we used for the Earth as in part C. How does this compare with your answer obtained from the plot above? G) If the force of gravity is pulling you toward the center of the Earth, why don't you move toward the center of the Earth? Is there another force that counters gravity?