.1" There seems to be an outlier. Enter as a point: a. (any) = \"1136) 0' To determine if this is truly an outlier, we first need to find the standard error of the estimate, 56. Find the regression equation, round the slope and y-intercept to 2 decimals, and then use that equation to find the standard error. Round this answer to one decimal. b. 38: '91 'lo" What y-value is the cutoff beyond which the point (11, 36] would be considered an outlier? c. The cutoff is y = 12 X 0" d. Is the point (11, 36) an outlier? f\\ 'w' No