1. Two identical curling stones of mass 17 kg collide. The first stone hits the stationary second stone with a constant velocity of 6.0 m/s [N]. If the velocity of the first stone is 2 m/s [N 20"W] after the collision, find the velocity of the second stone after the collision. Assume that effects due to friction are negligible. 2. A block of mass 5 kg is placed next to a spring with a spring constant of 350 N/m on a flat, horizontal, frictionless surface. The block is then pushed against the spring and compresses it a distance of 0.05 m. Find the acceleration of the block the instant it is released.1. From conservation of momentum along x-axis is, 0 =17[2sin(20) +17v, v. =-0.684 m/s From conservation of momentum along y-axis is, [(17)(6)] =17[2cos(20) +17v, v. = 4.12 m's Thus, the required value of velocity is, V = x = ((-0.684) +(4.12) av=4.17 m's North stone 1 stone 2 West East stone 1 South2. From Hooke's law, the value of spring forc, F = kx (1) Again, from Newton's law of motion. F = ma (2) Due to the spring force, the spring will start moving. Equating equation (1) and (2), ma = kx kx (350) (0.05) ( = - a=3.5m/'s