#1) Two pictorial representations of the molecular orbitals for cyclobutadiene are shown below. NOTE: Dashed lines represent nodes; Y2 and Y: are degenerate): A B gogo gl sg gigs 42 43 44 (Cyclobutadiene),Ni, pictured below, is a hypothetical molecule with eclipsed rings. The molecule has Dan point group symmetry. a) As we did with other metal-sandwich systems, use the 8 pa orbitals of the two rings as a basis set, and come up with the reducible representation. Then find the irreducible representation. Show your work in the table below. D4h E 2C4 C2 2C22C2" i 2S4 On 20, 20, h=16 /16 A2g B1g Ni Eg Alu Azul Blu Bu E b) Draw the set of Group Orbitals (for both rings together), with the proper Mulliken Symbols. c) Identify the metal orbitals which will have the correct symmetry to overlap with the Group Orbitals you drew in Part (c). d) Draw the M.O.'s of the whole molecule (metal orbital plus orbitals for both rings). #1) Two pictorial representations of the molecular orbitals for cyclobutadiene are shown below. NOTE: Dashed lines represent nodes; Y2 and Y: are degenerate): A B gogo gl sg gigs 42 43 44 (Cyclobutadiene),Ni, pictured below, is a hypothetical molecule with eclipsed rings. The molecule has Dan point group symmetry. a) As we did with other metal-sandwich systems, use the 8 pa orbitals of the two rings as a basis set, and come up with the reducible representation. Then find the irreducible representation. Show your work in the table below. D4h E 2C4 C2 2C22C2" i 2S4 On 20, 20, h=16 /16 A2g B1g Ni Eg Alu Azul Blu Bu E b) Draw the set of Group Orbitals (for both rings together), with the proper Mulliken Symbols. c) Identify the metal orbitals which will have the correct symmetry to overlap with the Group Orbitals you drew in Part (c). d) Draw the M.O.'s of the whole molecule (metal orbital plus orbitals for both rings)