MTH101A PROBLEM SET 1 Equations (Linear, Quadratic, Rational, Equations Involving Absolute Values) 1. Find the solution set of each equation. Show complete solutions and indicate the property of equality that you used in each line. Using your answer, determine whether the equation is an identity, a conditional equation, or a contradiction. No need to verify. (4 points each) Example: 8. 9. 1. 3(x-3) = 4(2x + 1)-3x 2. 8b+4(4b-3) = 4(6b+4)-4 3. 4(-8c+5)=-32c-26 4. 8r = 162. The solution.x = 3 makes a denominator in the given equation zero. Hence, there is no solution or SS: (). This is a contradiction. 5. 3p + 19p+20=0 6, 9(-2)+6(1-2)=121-25 7. (x+13)(x-5)= 9x + 60x + 19 4 17.256 18. 1+ 7 6 2x =1+ - 3)()-(-3)(1+3) 2x=(x-3)+6 2x = x + 3 2x-x=x+3-x (Addition) = 2 + 9-2 q+1 5 2-3 2x2-78 +6 -64 0 6 x-3 -(4+3m)-8= 5m +9 10. 11. 15. 2y +5 6y-1 19. 15 20. 16. 4 (Multiplication) = 2-x 5 2x-1 2x+1 2x-1 12. la-9-1+4a 13. 12-71142+61 14. 14-3h1=2h-11 + 3w 3x 2x-3 3y + 5 = 4(+) -s(+1) + 12w-15 18 = 2 1 x+3 u-12 -20u +36 +1=0 3(x+7x)-14x +3 2x + 3x-9 3 5-18