1. What is the domain of Y^2/16 - X^2/36 in interval notation 2. Find the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (Y-1)^2= 16(x + 6) 3. Convert the equation to standard form by completing the square on x or y. Then find the vertex, focus, and directrix of the parabola. Finally, graph the parabola. Y^2-4y + 16x + 4 = 0 4. Find the standard form of the equation of the parabola satisfying the given conditions. Vertex: (5, -2); Focus: (5, -6) 5. Find the focus and directrix of the parabola with the given equation. Then graph the parabola. Y^2- 32x = 0 6. Find the focus and directrix of the parabola with the given equation. Then graph the parabola. X^2= -8y