1. When m-is even number and n-is odd number, S cost x sin" x da will be evaluate as n = odd => n = 2k + 1 for k integer. Therefore, sin"x = sin2k+1x = (sin2x) K * sin x. We know that sin2x = 1 - cos2x, thus Sinnx = (1- cos2x) k sin x Then cosm x sin" ada = fcosm x (1 - cos x) sin x Let's assume u = cos x, du = - sin x dx - S (1 - u2)" um du 2. For this expression, we will discuss three options: Vac2 + a2, -22 + a2, and Vac2 - a2 . To integrate V x2 + a2 , the domain is R. We restrict our choice to the trigonometric functions that have a range R. Thus, we have x = atand or x = acote as substitutions with >11. What is the strategy for evaluating trigonometric integral in given form, when m-is even number and n-is odd number. f 003'" x sin\" xdx 2. What is the strategy for integration or what kinds of substitutions are recommended when certain radicals appean +x2 + (12 Please consider all 3 options