Question
1. You are turning a component to a diameter of 50.8 mm. The cylindrical stock has a diameter of 57.2 mm. The spindle speed
1. You are turning a component to a diameter of 50.8 mm. The cylindrical stock has a diameter of 57.2 mm. The spindle speed is set to 240 rpm. The feed is 0.42 mm/rev. (a) What is the material removal rate? (b) The steel that we are cutting has a specific energy of 5.1 J/mm. What is the required cutting power? (c) What is the cutting speed?
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Niebels Methods, Standards and Work Design
Authors: Andris Freivalds, Benjamin Niebel
13th edition
978-0073376363, 73376361, 978-0073376318
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