10. 11. 12. 13. 14. 15. 16. 1?. 18. 19. 2D. Differentiate: y = (a: +1}(s:3 + 8s: + 1} . . . . 63:2 +1 Use the quotient rule to differentiate. y $2 + 2 Differentiate' 5 ' y _ +1 2 If y = (3:2 + 4?. find $- Compute 3: for y = i/E and u = 3:2 + 1 using the chain rule. State your answer in terms of a: only. Use implicit differentiation of the equation below to determine the slope of the graph at the given point. . 1 xy5=16,x=Z,y=4 Differentiate: y = 524.9\" Differentiate: y = V e\" + 15 Differentiate: y = evx+15 . . . . e93 + 7&9\" Simplify and then differentiate: f(x) = T Find the value of :1: at which the function f(:i:) = (4:1: 3}e4_3" has a possible relative maximum or minimum point. {Recall that e\" is positive for all m.) For each of these values of m, use the second derivative test to determine if the point is a relative maximum. a relative minimum or neither