(10) (5 pts) o = ?E [X2]- (E[X])2, where E is the expectationoperator (e.g., E[X] ? X). Give two reasons why this is aparticularly bad way to compute standard deviation for a large dataset. (10) \( (5 \mathrm{pts}) \sigma=\sqrt{\mathrm{E}\left[X^{2}\right]-(\mathrm{E}[X])^{2}} \), where \( \mathrm{E} \) is the expectation operator \( (\mathrm{e} . \mathrm{g} ., \mathrm{E}[X] \approx \bar 1 answer