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10. a) CI+B F2 FJ + G b) FT (DV-GF+) C + B +fz| = c) (= 1, G = 1, DV=SKN, F2 =
10. a) CI+B F2 FJ + G b) FT (DV-GF+) C + B +fz| = c) (= 1, G = 1, DV=SKN, F2 = 33KN, FT = 5- FT + B +3, B = 2FT -8, TO GET FT = 5KN AND B=10-8 THEN B = 2KN 2) F2 = 4KN, B=2KN, FT = 5-FT'+2+4 2FT= FT = 5.5 off SET=5.5-5 = 0.5kN OUTPUT= F Mass M Piston A F2 FIG. 5 Piston B
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Engineering Mechanics Statics
Authors: Russell C. Hibbeler
11 Edition
9780132215091, 132215004, 132215098, 978-0132215008
