(10) (a) Find the tangent plane to the function f (as, y) = V20 m2 7y2 at (2,1). (b) Find the linear approximation of the function f (:13,y) = V20 m2 7y2 at (2,1). (0) Show that an approximation of the number 20 (2.00351)2 7(1.00019)2 is 3.00278. ((1) What is the exact value of the number 20 (2.00351)2 7(1.00019)2? (e) Why is the approximation of 1/20 (2.00351)2 70.00019)2 greater than the ex- act value