[10] In a sample space S of 40 outcomes from which one is selected randomly, there are 4 events A, B, C, and D that exhaust the sample space. A & C are disjoint. C & D are disjoint. A, B, and D share one outcome. P(A)=12/40, P(B)=15/40, P(C)=11/40, and P(D) = 15/40. Moreover, we know P(A | B)=1/5, P(A | D)=2/5, and P(B & D)=4/40. What is P(B & C)