10. Now place the intensity meter on the incident beam, and you should measure 100%. What is the intensity of the reflected beam, and the refracted beam in % with respect to the intensity of the incident beam? a. Reflected around 23% and refracted around 77% b. Reflected around 77% and refracted around 23% c. Reflected around 0% and refracted around 100% Set Air as the Upper medium and change the Lower medium to Air also, by sliding the button on the lower refractive index box from Water to Air, or n=1.00. Set angle of incidence to 450. 11. What can you say about the reflected and refracted beams in this situation? a. As the Upper and Lower media are the same, there is no reflected beam; also, the incident beam travels through the media without being refracted. b. As the Upper and Lower media are the same, the beam is reflected only. 12. Now place the intensity meter on the incident beam, and you should measure 100%. What is the intensity of the beam in the Lower medium? a. 0% as there is no reflection. b. 0% as there is no refraction. c. 100% as the beam is travelling in the SAME medium.For questions 6 to 10, set Air as the Lower medium and change the Upper medium to Water. Set angle of incidence to 450 6. With the incident angle set at 450, what is the angle of reflection? a. 00 b. 30 c. 450 niar d. 60 7. With the incident angle set at 450, what is the angle of refraction? a. 0o b. Between 30 to 350 c. Between 43 to 470 d. Between 60 to 750 8. Using Snell's law, and given that the refractive index of Air is 1 and that of Water is 1.33, what is the value of the refracted angle (incident angle set at 45 )? a. 0o b. 450 c. 60 d. 70Ray Figure 2 Wave 5.29% Material Air 4 30 30 Intensity Index of Refraction (n) 1.00 60 60 LLLL Air Water Glass .90 90 60 Water 60 Material 4 Index of Refraction (n) 1.33 30 Air Water Glass Normal Bending Light PHET = Intro Prisms More Too9. Is the refracted beam closer to or further away from the normal compared to the incident beam, and why? a. The angle the refracted beam makes with the normal is smaller than the incident angle because the beam is going from a medium of higher refractive index to a medium of lower refractive index. b. The angle the refracted beam makes with the normal is the same as the incident angle because the Law of reflection states that the angle of incident is the same as the angle of reflection13. Keep/set both the Upper and Lower media to Air. Now, increase the refractive index of the lower medium all the way to Glass (n=1.5) and observe what happens to the refracted ray. Which of the following statement best describes your observation? a. As the refractive index of the lower medium increases from air to glass, the angle the refracted beam makes with the normal increases. b. As the refractive index of the lower medium increases from air to glass, the angle the refracted beam makes with the normal decreases. c. As the refractive index of the lower medium increases from air to glass, the angle the refracted beam makes with the normal remains the same.14. Set the Upper medium to Air and the Lower medium to Glass (n=1.50). Set the angle of incident at 60. Using Snell's law, and given that the refractive index of Air is 1 and that of Glass is 1.50, what is the value of the refracted angle (incident angle set at 60 )? a. 00 b. 35.20 C. 450 d. 60 15. Keep Upper medium Air, and Lower medium Glass, and incident angle set at 60. Now place the intensity meter on the incident beam, and you should measure 100%. What is the intensity of the reflected beam, and the intensity of the refracted beam in % with respect to the intensity of the incident beam? a. Reflected around 17% and refracted around 83%. b. Reflected around 83% and refracted around 17%. c. Reflected around 0% and refracted around 100%