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(+10 ) Problem #14 in the Chapter review problems on Page 199 Answer a provided a. 5.18.35 b. c. (+10 ) Problem #15 in the

(+10 ) Problem #14 in the Chapter review problems on Page 199

Answer a provided

a. 5.18.35

b.

c.

(+10 ) Problem #15 in the Chapter review problems on Page 199

Answer c provided

a.

b.

c. 0000 1000 0000 1100 0001 0100 0000 1101

(+10 ) Convert the following twos complement representations to its equivalent base 10 value. Recall if the most significant bit is a 1 the number is negative

1101110 _______

0110110 ________

(+5 ) The entire URL required to retrieve the Web document named bulldogs.html from the Webserver at animals.org assuming that the document is stored in the directory named dogs:

a. https://animals.org/dogs/bulldogs.html

b. http://animals.org/dogs/bulldogs.html

c. http://dogs.animals.org/bulldogs.html

d. http://animals.org/dogs.bulldogs.html

(+5 ) Can the following 2s complement calculation be performed using 6 bits?

32 - 31

a. Yes the result is 000001

b. No, -31 cannot be expressed using 6 bits

c. No 32 cannot be expressed using 6 bits

d. Yes the result is 000011

(+5 ) Can the following 2s complement calculation be performed using 4 bits?

-8 + 7

a. Yes the result is 1111

b. Yes, the result is 0001

c. No -8 cannot be expressed using 4 bits

d. No 7 cannot be expressed using 4 bits

---

(+20) Provide a python program to determine the parking fees at the airport based on the following time constraints :

Any amount of time less than or equal to one hour, the parking fee is 5.00. This means if your parked for 5, 15, 55 or 60 minutes you pay $5.00

Minutes parked

Hrs*Fee=parking fee

25 minutes (0 hour and 25 minutes)

1*5.00

05 minutes (0 hour and 5 minutes)

1*5.00

55 minutes (0 hours and 55 minutes)

1*5.00

30 minutes (0 hour and 30 minutes)

1*5.00

10 minutes (0 hour and 10 minutes)

1*5.00

60 minutes (1 hour and 0 minutes)

1*5.00

Any amount of time greater than one hour but less than or equal to 5 hours (300 minutes), the parking fee is 4.00 per hour and any fraction thereof. This means:

Minutes parked

Hrs*Fee=parking fee

65 minutes (1 hour and 5 minutes)

2*4.00

95 minutes (1 hour and 35 minutes)

2*4.00

120 minutes (2 hours)

2*4.00

135 minutes (2 hour and 15 minutes)

3*4.00

180 minutes (3 hour and 0 minutes)

3*4.00

195 minutes (3 hour and 15 minutes)

4*4.00

240 minutes (4 hours)

4*4.00

260 minutes (4 hours 20 minutes )

5*4.00

300 minutes (5 hours)

5*4.00

Any amount of time greater than 5 hours, the parking fee is 2.00 per hour and any fraction.

Minutes parked

Hrs*Fee = parking fee

320 minutes (5 hour and 20 minutes)

6*2.00

400 minutes (6 hour and 40 minutes)

7*2.00

800 minutes (13 hour and 20 minutes)

14*2.00

825 minutes (13 hour and 45 minutes)

14*2.00

600 minutes (10 hours)

10*2.00

Use the following test cases to make sure the results of your code are as expected

Minutes parked Cost

Suggested template PLEASE modify as needed :
rate1 = 5 # $5 rate rate2 = 4 # $4 rate rate3 = 2 # $2 rate #various calculations using ROUND, INT % / // functions and operators 
#these calculations can be removed from your final code 
Illustrative purposes only REMOVE from your code if NOT needed 
 x = round(25.3456, 1) print("1 x == ", x) x1 = round(25.3456, 2) print("2 x1 == ", x1) y = int(24.88) print("3 y == ", y) z = 174 % 60195 print("4 Z == ", z) a = 33/60 print("5 a == ", a) b = 33//60 print("6 b == ", b)
 fee = 0.0 # initialize m = int(input(" Please enter number of minutes parked...")) if (0 < m and m <= 60 ): #table 1  hrs = int(m/60) + 1 fee = hrs*rate1 print("Parking fee for ", m, " minutes is $", fee) # now for table 2 elif (m > 60 and m <= 300): # table 2  # calculations needed print('we are in table 2 fee is ', fee) elif ( m > 300): # table 3 #calculations needed print('we are in table 3 fee == ', fee) else: print("error negative minutes", m )

1 x ==25.3

2 x1 ==25.35

3 y ==24

4 Z ==54

5 a ==0.55

6 b ==0

Please enter number of minutes parked...

we are in table 2 fee is0.0

:

: minutes parked

: Parking fee

Your program should ask the user for minutes parked, use the various functions/operators as needed to determine in which table 1, 2 3 the minutes falls into, compute and output the parking fee

Let m = minutes parked

fee = parking fee

Please make sure your code uses the constants:rate1 rate2 rate3

Once you have determined your algorithm, try it for several of the minute examples provided in the tables above for accuracy

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