(10%) Problem 7: A 65.7 kg man floats in freshwater with 3.03% of his volume above water when his lungs are empty, and 5.06% of his volume above water when his lungs are full. * Calculate the volume of air, in liters, that he inhales. (This is called his lung capacity.) Neglect the weight of air in his lungs. Grade Summary Vair= - 7.39 * 10( - 6) L Deductions 0% Potential 100% sin() cos () tan() IT ( ) 7 8 9 HOME Submissions cotan() asin() acos() E 4 5 6 Attempts remaining: 997 atan() acotan() sinh() * 1 2 3 0% per attempt) cosh() tanh() cotanh() + 0 END detailed view o Degrees . Radians VO BACKSPA DEL CLEAR 0% NH 0% Submit Hint Feedback I give up! Hints: 3 for a 0% deduction. Hints remaining: 0 Feedback: 1 for a 0% deduction -Use Newton's second law and the buoyant force to No meaningful feedback available for the current determine the fraction of his volume which is submerged. submission. The difference between the full lungs and empty lungs is only due to the volume change of his body, since the weight of the air is negligible. -Since his weight doesn't change, neither does the buoyant force