(10%) Problem 9: A bowling ball of mass m = 1.3 kg is resting on a spring compressed by a distance d = 0.44 m when the spring is released. At the moment the spring reaches its equilibrium point, the ball is launched from the spring into the air in projectile motion at an angle of 0 = 310 measured from the horizontal. It is observed that the ball reaches a maximum height of h = 4.4 m, measured from the initial position of the ball. Let the gravitational potential energy be zero at the initial height of the bowling ball. *50% Part (a) What is the spring constant k, in newtons per meter? k = 579.11 Grade Summary Deductions 0% Potential 100% sin() cos() tan() ( 7 8 9 HOME asin() acos() E INAL 4 5 6 Submissions cotan() atan() acotan() sinh() * 1 2 3 Attempts remaining: 994 (0% per attempt) cosh() tanh() cotanh() + 0 END detailed view o Degrees . Radians VO BACKSPA DEL CLEAR 0% 0% Submit Hint Feedback I give up! WN 0% Hints: 4 for a 0% deduction. Hints remaining: 0 Feedback: 0% deduction per feedback. -Does the x or the y-component of velocity change? What portion of the initial kinetic energy is converted to gravitational potential energy? You will need the launch angle for this part. -Use the principle of energy conservation to equate the y- component of the kinetic energy with the increased gravitational potential energy. -Do you know the velocity in terms of the spring constant? 4 50% Part (b) Calculate the speed of the ball, vo in m/s, just after the launch