10. Suppose you are designing a sliding window protocol for a 10-Mbps point-to-point link to the moon, which has a one-way latency of 1.25 seconds. Assuming that each frame carries 10KB of data, and SWS = RWS (Sender window size is equal to the receiver window size) what is the minimum number of bits you need for the sequence number? - 10 pts Use- 1Mbps=1024Kbps, and 1KB=1024 Bytes (Hint: Compute RTT, Delay*Bandwidth, determine number of frames required, to keep the pipe full)