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10. The orbital radius of Venus is 0.72Rs (orbital radius of Earth). How many days is a Venusian year? b. 263 days - hy displayment
10. The orbital radius of Venus is 0.72Rs (orbital radius of Earth). How many days is a Venusian year? b. 263 days - hy displayment at a pow a. 223 days c, 312 days d. 507 days 2's acceration 11, Astronauts in an orbiting space shuttle experience a sense of weightlessness, Which of the following statements best explains this phenomenon? a. The shuttle exists in a zero gravity environment The shuttle is not affected by Earth's gravity The force of gravity in the shuttle decreases as its distance from Earth increases d. The shuttle is freely falling toward the Earth Vo - us 12. The gravitational force between two unknown masses is 24.0N when the distance of separation is 25.0m. If the distance is increased to 50.0m, the force will become: a) 96.ON b) 48.0N Fg=mg c) 12.ON d) 6.00N Ergh a max Problems: 1. (5) A 500g block on a spring is pulled a distance of 20.0cm from equilibrium and released. The = - kx subsequent oscillations are measured to have a period of 0.80s a. (2) What is the spring constant? Fe = kx GMm spring constant formula F = kx = = (k) (0.2m ) W = F w = m = 5009-95 - 20.0 0m - 0.2m k=mg = (0. 5kg) (9:81 m/s) - C. 80s xeg (0.2m) 24:525 2GM b. (2) Assuming that energy in the system is 100% conserved, at what distance from V = 1 equilibrium is the block's speed 1.0m/s? distance in 1. am/s K = m = v ( * ) ( 42_ x 2 ) ( 24.52 ) GMm ential E motor Force F. = BIL c. (1) What is the object's angular frequency? asisal frekens = w V - W = 217 27 ference C. 80s - 7:85 75 Difference rm field Difference Electric Field 2. (4) A horizontal rod is attached to a cord and spring, and supports an unknown mass hanging on the end rential diffe of the rod as shown. The spring scale reads a tension of 15.8N. Construct a torque diagram only, and calculate the mass of the unknown object. torque Qiq V = 29 Spring scale Eg = v.q -2.04g c. 60 m Hinge S 2.0 kg- tension = 15:8N -0.60 m the moss = ? TCW = TCCW
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