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100 Newtons Region 1; IJ-k = 0.1 Region 2; pk = 0 Region 3; pk = 0.5 Problem #5: A box is initially at rest
100 Newtons Region 1; IJ-k = 0.1 Region 2; pk = 0 Region 3; pk = 0.5 Problem #5: A box is initially at rest on a surface where the coefficient of kinetic friction is equal to 0.1 (assume friction immediately shifts to kinetic upon applying a force}. A 100 Newton applied force angled as shown above then pushes the box across a region (Region 1) for 5 seconds. The box then enters a new region (Region 2) where the surface is frictionless and the applied force no longer acts on the box the box is in this region for an addition 5 seconds. Finally, the box enters a third region (Region 3) where the coefficient of friction is 0.5 and the box comes to rest. a. Calculate the acceleration in each region. b. Calculate the total time and the total distance that the box travels. c. Make a brief sketch of the following graphs for the entire process: position vs. time, velocity vs. time, and acceleration vs. time. cl. Suppose that Region 3 does not exist and instead the end of Region 2 represents the end of a tabletop, which is 5 meters above the ground. What would be the time of flight of the box? Its range? e. Genermr questions unrelated to the given problem: Determine whether each statement below is TRUE or FALSE. If the statement is FALSE, justify your response. i. If the acceleration of an object is zero then we know that there must be no forces acting on it. ii. A force is required to keep an object moving at constant velocity in all circumstances. iii. Objects are easier to lift on the Moon (rather than the Earth) because they have less mass on the Moon. iv. If an object's velocity is zero, its acceleration must be zero as well. v. If only one force is acting on an object then it can move with a constant velocity
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