1:01 a eversity.blackboard.com Home Review Test Submission: Learning Check 4.5 Question 8 0 out of 1 points A random sample of statistics students X were asked to estimate the total number of hours they spend watching television in an average week. The responses are recorded in the table below. Use this sample data to construct a 90% confidence interval for the mean number of hours statistics students will spend watching television in one week. 0 3 20 9 5 10 1 10 4 14 2 4 4 5 Round the mean, standard deviation and EBM to 4 places, then round answer to 2 places at the end. Fill in the blank, round to two decimal places: ([x1],[x2]) Specified Answer for: x1 6.13 Specified Answer for: x2 5.51 Response Use Excel to find the Feedback: mean, standard deviation and use the online calculators for the t value since t depends on n for the EBM.1201 . ? E} H eversity.blackboard.com Review Test Submission: Learning Check 4.5 Question 3 0 out oft points '- One hundred eight Americans were 'j surveyed to determine the number of hours they spend watching television each month. It was revealed that they watched an average of 151 hours each month with a standard deviation of 32 hours. Assume that the underlying population distribution is normal. Identify the following: a. Y = b. S x = c. n = Selected Answer: _ a. X = 32 b. 5x: 108 c n = 32 n = 108 Answers: a Y = 32 b. s)( = 108 c n = 32 n = 108 a. i = 151 b. 5x = 32 c. n = 108 a Y = 32 b 5,. = 151 c n = 108 a Y = 32 1201 . ? [:J' H eversity.blackboard.com ame U) 6) Review Test Submission: Learning Check 4.5 Question 6 0 out of1 points f' One hundred eight Americans were surveyed to determine the number of hours they spend watching television each month. It was revealed that they watched an average of 151 hours each month with a standard deviation of 28 hours. Assume that the underlying population distribution is normal. Calculate the EBM.Use a 99% Confidence Level Use 3 decimal places until the end calculation then round to two decimal places. Selected Answer: 0.816 Response Notethisis Feedback: 99% confidence level. You should have found 2 to be 2.623. Question 7 1 out of1 points 7'4 an hwmnther 1201 . ? [E' H eversity.blackboard.com ame Q) @ Review Test Submission: Learning Check 4.5 ll Question 5 0 out of1 points ff One hundred eight Americans were '46 surveyed to determine the number of hours they spend watching television each month. It was revealed that they watched an average of 151 hours each month with a standard deviation of 32 hours. Assume that the underlying population distribution is normal. Construct a 99% condence interval for the population mean hours spent watching television per month. Round to two decimal places: ([x1],[x2]) Specified Answer for: x1 143.06 Specified Answer for: x2 158.94 Question 6 0 out of1 points {if One hundred eight Americans were j surveyed to determine the number of hours they spend watching television each month. It was revealed that they watched an average of 151 hours each month with a standard deviation of 28 hours. Assume that the underlying population distribution is normal. 1:01 a eversity.blackboard.com Home Review Test Submission: Learning Check 4.5 Question 4 0 out of 1 points One hundred eight Americans were X surveyed to determine the number of hours they spend watching television each month. It was revealed that they watched an average of 151 hours each month with a standard deviation of 32 hours. Assume that the underlying population distribution is normal. Which distribution should you use for this problem? Selected normal Answer: Answers: normal student t distribution neither Response Review the definition of Feedback: normal and student t distributions. Question 5 0 out of 1 points One hundred eight Americans were