11. A 2 kg box is placed at the top of a slope, compressing a spring with a stiffness of 30 N/m by 50 17. A worker exerts a force of magnitude F at an angle 0 downwards from the horizontal on a box cm from equilibrium, then released from rest. It descends the slope at an angle of 45 degrees of mass m as it moves a distance d to the right across a rough surface. The coefficient of kinetic from the horizontal, with a height of 10 m. It encounters a frictional patch (with HK = 0.3) friction between the box and the surface is My, and the acceleration due to gravity is g. Which spanning 3 m. Afterward, it encounters another spring (k = 30 N/m), compresses it, and then of the following is the correct expression for the change AK in the box's kinetic energy during travels back up the slope. What is the maximum height the box will reach? Everywhere is this process? Here, it may help to assume the system is the box, the surface, and Earth, while frictionless except the 3m patch in the figure the worker and associated force are in the environment. m AK = HK(F sine + mg)d A. 8.39 m B AK = - HK (F sin 0 + mg)d B All the way up to the original position C. AK = F cos ed C. 8.20 m D. AK = (F cos 0 - Hxmg)d D. 9.10 m E. AK = (F cos 0 - HKF sin 0 - ukmg)d E. 9.29 m 9. A 10kg mass is connected to an ideal spring with a spring constant of k = 100 N/m, positioned horizontally on a frictionless table. The spring is initially stretched by 0.50 m (measured from equilibrium). Upon releasing the mass from rest, it moves towards the equilibrium position. At what position x of the mass (where x = 0.0 m when the spring is in equilibrium) will the system's total energy be equally distributed between kinetic energy and elastic potential energy? A. 0.13 m B 0.10 m C. 0.25 m D. 0.35 m E. 0.15 m