11. Express (edx as a limit of Riemann sums. Use the right endpoint of each subinterval as the sample point. 5 points. Find antiderivative = ex \\ ! = [e' ] - Je . J e - 1 = 1. 78 28192 or 1.72 . To check Find Ax [ o , I J n = 4 Ax = b - a 1-0 OF 0. 25 n 4 . 125 . 576 . 625 . 876 0. 25 0 . 5 0. 75 Area of Midpoint AM = Ax [ f (0 . 125) + f (0. 375) + f(0.625) +1/0.875) ] = 0.25 [ 2 0. 125 0. 375 4 0 . 625 + 0.873 7 = 1 7 1 3 815 27 -or 1 72