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11. Suppose X follows a normal distribution with mean 5 and variance 16. That is X ~ Normal(5, 16). The 90% percentile of X is:

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11. Suppose X follows a normal distribution with mean 5 and variance 16. That is X ~ Normal(5, 16). The 90% percentile of X is: (a) 1.28 (b) 10.12 (c) 5 (d) not computable with the given information. Explanation

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