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The data from car crash tests for four different vehicle size categories (Small, Midsize, Large, and SUV) with measured amounts of left leg femur force (kN) results in the following Minitab display. Using a 0.05 significance level, test the claim that the four vehicle size categories have the same mean force on the femur of the left leg. Does size of the car appear to have an effect on the force on the left femur in crash tests? Analysis of Variance Source DF Adj SS Adj MS F-Value P-Value Size 3 0.5418 0. 1806 0.47 0.705 Error 44 16.9092 0.3843 Total 47 17.4510 Determine the null hypothesis. Ho Determine the alternative hypothesis. H 1 Determine the test statistic. The test statistic is ]. (Round to two decimal places as needed.) Determine the P-value. The P-value is (Round to three decimal places as needed.) Does size of the car appear to have an effect on the force on the left femur in crash tests? Ho- There sufficient evidence at a 0.05 significance level to warrant rejection of the claim that the four vehicle size categories have the same mean force on the left femur in crash tests.Determine the null hypothesis. Dete Hy : All of the means are different Dete The ROL Hy > H2 > 3 > P4 Dete My = 12 = H3 = H4 The ROL At least one of the means is different from the others DoesDetermine the alternative hypothesis. H 1 Dete The (ROL Hy > H2 >3 > H4 Dete H1 = 12 = 13 = P4 The (ROL All of the means are different Doe: Hy = 12 ChiSq <.0001let o denote population standard deviation of the pulse rates women beats per minute identify null and alternative hypotheses. ho: cimals. do not round. identif stic. al places as needed. identit imal h: h : identil state i about hypothesis well final conclusion that addresses original claim.state claim. hypothesis. there v sufficient evidence to claim have a equal minute. results indicate significant using range rule ange from for estimating effective in this case. accept fail reject rejectstate thumb with jute is isstate estim support warrant rejection ofstate notstate nota random sample births new york included boys be used test common belief proportion male complete parts through a. testing babies values p p. three decimal b. samples size what proportions are at least extreme select correct choice below fill answer box within your choice. those greater than or less c. to. d. both method randomization resamples it found them . significance level should concluded not407 supportthe iq scores subjects low lead levels their blood another high n x s were collected. statistics summarized accompanying table. assume two independent simple selected normally distributed populations. deviations equal. below. h2 use mean score people higher levels. hypotheses consists oa. hy sh2 ob. h1> H2 H 1 : H1 > H2 OC. Ho: H1 = H2 OD. Ho: H1 = H2 H 1: 1 1 > H2 H1 : H1 # H2 The test statistic is . (Round to two decimal places as needed.) The P-value is .(Round to three decimal places as needed.) State the conclusion for the test. O A. Reject the null hypothesis. There is not sufficient evidence to support the claim that subjects with low lead levels have higher IQ scores. O B. Reject the null hypothesis. There is sufficient evidence to support the claim that subjects with low lead levels have higher IQ scores. O C. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that subjects with low lead levels have higher IQ scores. O D. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that subjects with low lead levels have higher IQ scores. b. Construct a confidence interval appropriate for the hypothesis test in part (a).