11:15 X 35.11 1 14,0.41 1025. 92 9,6.90 $0.09 2509. 60 919:09 49:29 9429.56 27. 29 51. 69 267126 -103- 241 47- 63 92 68 .62 36.20 712 . 041 20.59 93574 16. 62 21 13 . 42 37. 58 1127. 61 34. 55 1193- 70 1 12. 74 1226- 71 34. 20 1211. 04 37. 73 1423-55 35-51 10 5 6. 90 346-15 10970. 035 421 . 31 |19 321 . 24 h, =ll X 346 .15 X, = 421. 31 = 46-21 2. 2 31. 47 S 2 = 19 281. 24 -/4213) SI = 3x - n, n , 9 9 , 2 K = 10470.035 1346 . 15 KS, = 2 209. 096- 2191.38 11 S, = 997. 276 - 990. 046 52 2 17. 7 46 8 1 = 7. 23 Notice that S> > s, of so we take the test statistic as F = 52 = 170 746 5 / 2 = 2. 45 4 7-23 rid f = ( n, -1 , n. - 1 ) = ( 9 =1, 11-1 )910 = (8 , 10 ) - Table value offF = 3017 Conclusion: Ho is accepted at 51. level since the calculated value of F / the table value. .: The varupances of the populations are equal3. Take the mean and standard deviation of data set A calculated in problem 1 and assume that they are population parameters ([1 and 0) known for the variable sh length in a population of rainbow trouts in the Goldwater River. Imagine that data set B is a sample obtained from a different population in Red River (Chapter 6 problem!). a) Conduct a hypothesis test to see if the mean sh length in the Red River population is different from the population in Goldwater River. b} Conduct a hypothesis test to see if the variance in sh length is different in the Red River population compared to the variance in the Coldwater population