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(12 points) The value of a pointer is a memory location, which can be interpreted as an integer as seen in a previous question. If

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(12 points) The value of a pointer is a memory location, which can be interpreted as an integer as seen in a previous question. If you want to see addresses printed as decimal numbers rather than hexadecimals, it is usually safe to cast address as an unsigned long and use the %lu format descriptor. What will get printed out when the following code is executed? Please explain your answer. Answer without correct explanation will not receive full credits for this question. #include typedef unsigned long ul; int main() char int double long double *pc = NULL; *pi = NULL; *pd = NULL; *pld = NULL; printf(" %5lu %lu %5lu %5lu %5lu %5lu ", (ul) (pc + 1), (ul) (pi + 1), (ul) (pd + 1), (ul) (pld + 1), (ul) (pc + 3), (ul) (pld + 3)); return 0

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