A JFET transistor with a resistor RS creates a constant current source in the figure above. The value of the resistance R=1400 so that lo is 4 mA. Both Rc=27500 so that Ve is about 6.5V. Two BC546B BJT transistors form the differential amplifier. The supply voltage is 12 V. a) Let the input Vi1 on transistor Q1 get the signal voltage: Vil = 0,05- cos (2T-10. t) V The input Vi2 on to transistor Q2 is just connected to ground and = OV. Calculate differential gain for the differential amplifier. b) Now set both inputs Vi1 on Q1 and Vi2 on Q2 to be Vil = V2 = 1,0-cos (2T-10. t) V Calculate differential gain for the differential amplifier. Vil Rc Vol Q3 VE +12 V Vo2 |1Q Rs -12 V Rc Q