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1295 300 If the eigenvalues of are 1 and 2 with 1 > 12 then: 5590 - 1295 A1 = and 12 = 1295 300

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1295 300 If the eigenvalues of are 1 and 2 with 1 > 12 then: 5590 - 1295 A1 = and 12 = 1295 300 An eigenvector of associated with X] is: 5590 - 1295 1295 300 An eigenvector of associated with 12 is: 5590 - 1295 4 9 [ ] and [ ] are eigenvectors of the matrix [ 43 130 1 2 ' 10 42 4 What is the eigenvalue corresponding to [ 1 ]? 9 What is the eigenvalue corresponding to [ 2 ]? The velocity field of a certain fluid is: v(a:, y, z) = (4 moos(z) meg 005(9), ycos(z), ez cos(y)) The surface S is the portion of 3:2 + 92 + 22 : 1 for which a: > 0, oriented away from the origin. The flux of the fluid across 5 is: ' ' (Suggestion: Use the Divergence Theorem. Note that the surface S is not closed.) The foruth degree MacLaurin polynomial for the solution to this IVP: "' + 4xy' + 3y = 0 with initial conditions: y(0) = 3, y'(0) = 2 is: PA(a) =The velocity field of a fluid is given by: v(x, y, z) = (1, y sin z, cos z) The surface S is the part of the cone (x - 6) = 92 + 422 where 0

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